-10-4x^2=-302

Solution for -10-4x^2=-302 equation:

-10-4x^2=-302

We move all terms to the left:

-10-4x^2-(-302)=0

We add all the numbers together, and all the variables

-4x^2+292=0

a = -4; b = 0; c = +292;
Δ = b2-4ac
Δ = 02-4·(-4)·292
Δ = 4672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4672}=\sqrt{64*73}=\sqrt{64}*\sqrt{73}=8\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{73}}{2*-4}=\frac{0-8\sqrt{73}}{-8}
=-\frac{8\sqrt{73}}{-8}
=-\frac{\sqrt{73}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{73}}{2*-4}=\frac{0+8\sqrt{73}}{-8}
=\frac{8\sqrt{73}}{-8}
=\frac{\sqrt{73}}{-1}
$